Trigonometric Ratio And Identites — JEE Main Previous Year Questions

How many JEE Main questions come from Trigonometric Ratio And Identites?

Trigonometric Ratio And Identites has contributed 61 questions to Joint Entrance Examination (Main) papers between 2016 and 2026 — an average of about 6 questions a year. That count is measured from EByAi’s bank of 55,289 JEE Main questions, not estimated from a syllabus. Every one of the 61 questions carries a written, step-by-step solution, and each is tagged to Trigonometric Ratio And Identites within Mathematics, so you can drill this chapter across every year at once instead of hunting through paper PDFs. Practising a chapter’s full PYQ history is the fastest way to learn the patterns examiners reuse.

Sample Trigonometric Ratio And Identites questions from real JEE Main papers

These are 5 real questions from the bank — exactly as asked, with the answer one tap away. All 61 Trigonometric Ratio And Identites questions (with full written solutions) are available in practice.

1. Question 1 · JEE Main 2019

   The value of cos^2 10° – cos10°cos50° + cos^2 50° is
   1. (A)$$\frac{3}{2}+\cos 20^o$$
   2. (B)$$\frac{3}{4}$$
   3. (C)$$\frac{3}{2}(1+\cos 20^o)$$
   4. (D)$$\frac{3}{2}$$
   Show answerAnswer

   Answer: (B) $\frac{3}{4}$

2. Question 2 · JEE Main 2026

   The value of $\mathrm{cosec}10^{\circ }-\sqrt{3}\sec 10^{\circ }$ is equal to :
   1. (A)2
   2. (B)6
   3. (C)8
   4. (D)4
   Show answerAnswer

   Answer: (D) 4

3. Question 3 · JEE Main 2026

   The value of $\frac{\sqrt{3}\mathrm{cosec}20^{\circ }-\sec 20^{\circ }}{\cos 20^{\circ }\cos 40^{\circ }\cos 60^{\circ }\cos 80^{\circ }}$ is equal to
   1. (A)32
   2. (B)64
   3. (C)12
   4. (D)16
   Show answerAnswer

   Answer: (B) 64

4. Question 4 · JEE Main 2026

   If $\sin \left(\frac{\pi }{18}\right)\sin \left(\frac{5\pi }{18}\right)\sin \left(\frac{7\pi }{18}\right)=K$, then the value of $\sin \left(\frac{10K\pi }{3}\right)$ is:
   1. (A)$$\frac{\sqrt{3}+1}{2\sqrt{2}}$$
   2. (B)$$\frac{\sqrt{3}-1}{\sqrt{2}}$$
   3. (C)$$\frac{\sqrt{3}}{2}$$
   4. (D)$$\frac{1}{2}$$
   Show answerAnswer

   Answer: (A) $\frac{\sqrt{3}+1}{2\sqrt{2}}$

5. Question 5 · JEE Main 2026

   Let $$\frac{\pi }{2}$$\sin \left(\frac{15\theta }{2}\right)(\cos 8\theta +\sin 8\theta )+\cos \left(\frac{15\theta }{2}\right)(\cos 8\theta -\sin 8\theta )$ is equal to :
   1. (A)$\frac{\sqrt{2}-1}{\sqrt{3}}$
   2. (B)$\frac{\sqrt{2}}{\sqrt{3}}$
   3. (C)$\frac{1-\sqrt{2}}{\sqrt{3}}$
   4. (D)$-\frac{\sqrt{2}}{\sqrt{3}}$
   Show answerAnswer

   Answer: (C) $\frac{1-\sqrt{2}}{\sqrt{3}}$

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