Probability — JEE Advanced Previous Year Questions

How many JEE Advanced questions come from Probability?

Probability has contributed 32 questions to Joint Entrance Examination (Advanced) papers between 2016 and 2026 — an average of about 3 questions a year. That count is measured from EByAi’s bank of 18,502 JEE Advanced questions, not estimated from a syllabus. Every one of the 32 questions carries a written, step-by-step solution, and each is tagged to Probability within Mathematics, so you can drill this chapter across every year at once instead of hunting through paper PDFs. Practising a chapter’s full PYQ history is the fastest way to learn the patterns examiners reuse.

Sample Probability questions from real JEE Advanced papers

These are 3 real questions from the bank — exactly as asked, with the answer one tap away. All 32 Probability questions (with full written solutions) are available in practice.

1. Question 1 · JEE Advanced 2017

   Three randomly chosen nonnegative integers x, y and z are found to satisfy the equation x + y + z = 10. Then the probability that z is even, is
   1. (A)$\frac{1}{2}$
   2. (B)$\frac{36}{55}$
   3. (C)$\frac{6}{11}$
   4. (D)$\frac{5}{11}$
   Show answerAnswer

   Answer: (C) $\frac{6}{11}$

2. Question 2 · JEE Advanced 2025

   Three students $S_1,S_2,$ and $S_3$ are given a problem to solve. Consider the following events: U : At least one of $S_1,S_2,$ and $S_3$ can solve the problem, V : $S_1$ can solve the problem, given that neither $S_2$ nor $S_3$ can solve the problem, W : $S_2$ can solve the problem and $S_3$ cannot solve the problem, T : $S_3$ can solve the problem. For any event $E$, let $P(E)$ denote the probability of $E$. If $P(U)=\frac{1}{2}$ , $P(V)=\frac{1}{10}$ , and $P(W)=\frac{1}{12}$, then $P(T)$ is equal to
   1. (A)$\frac{13}{36}$
   2. (B)$\frac{1}{3}$
   3. (C)$\frac{19}{60}$
   4. (D)$\frac{1}{4}$
   Show answerAnswer

   Answer: (A) $\frac{13}{36}$

3. Question 3 · JEE Advanced 2023

   Consider an experiment of tossing a coin repeatedly until the outcomes of two consecutive tosses are the same. If the probability of a random toss resulting in head is $\frac{1}{3}$, then the probability that the experiment stops with head is :
   1. (A)$\frac{1}{3}$
   2. (B)$\frac{5}{21}$
   3. (C)$\frac{4}{21}$
   4. (D)$\frac{2}{7}$
   Show answerAnswer

   Answer: (B) $\frac{5}{21}$

Probability questions by year

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More JEE Advanced Mathematics chapters

• Limits Continuity And Differentiability (37)
• Matrices And Determinants (34)
• Definite Integration (24)
• Complex Numbers (22)
• 3D Geometry (20)

All JEE Advanced Mathematics chapters →JEE Advanced overview →